(x^2)+4x=63

Solution for (x^2)+4x=63 equation:

(x^2)+4x=63

We move all terms to the left:

(x^2)+4x-(63)=0

a = 1; b = 4; c = -63;
Δ = b2-4ac
Δ = 42-4·1·(-63)
Δ = 268
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{268}=\sqrt{4*67}=\sqrt{4}*\sqrt{67}=2\sqrt{67}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{67}}{2*1}=\frac{-4-2\sqrt{67}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{67}}{2*1}=\frac{-4+2\sqrt{67}}{2}
$